Evo pravi, takodje prosiri niz i for petlju, ako zelis da radis sa vecim brojevima
Code:
#include <iostream>
using namespace std;
int main()
{
char a[10];
char b[10];
char n[10] = {'1','2','3','4','5','6','7','8','9','10'};
int m = 0;
for(int i = 0; i <10;i ++)
{
cin >> a[i];
}
for(int j = 0; j < 10; j++)
{
if((b[j-1] == '0') && (a[j] == '0'))
{
b[j] = a[j+1];
m += 1;
if(a[j+1] != '0')
{
b[j] = n[m];
cout << b[j];
m = 0;
}
continue;
}
if((b[j] != '0'))
{
b[j] = a[j];
cout << b[j];
}
}
}